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SL Paper 2

Magnesium is a group 2 metal which exists as a number of isotopes and forms many compounds.

State the nuclear symbol notation, Z A X , for magnesium-26.

[1]
a.

Mass spectroscopic analysis of a sample of magnesium gave the following results:

Calculate the relative atomic mass, Ar, of this sample of magnesium to two decimal places.

[2]
b.

Magnesium burns in air to form a white compound, magnesium oxide. Formulate an equation for the reaction of magnesium oxide with water.

[1]
c.

Describe the trend in acid-base properties of the oxides of period 3, sodium to chlorine.

[2]
d.

In addition to magnesium oxide, magnesium forms another compound when burned in air. Suggest the formula of this compound

[1]
e.

Describe the structure and bonding in solid magnesium oxide.

[2]
f.

Magnesium chloride can be electrolysed.

Deduce the half-equations for the reactions at each electrode when molten magnesium chloride is electrolysed, showing the state symbols of the products. The melting points of magnesium and magnesium chloride are 922 K and 987 K respectively.

Anode (positive electrode):

Cathode (negative electrode):

[2]
g.

Markscheme

12 26 M g

a.

«Ar =» 24 × 78.60 + 25 × 10.11 + 26 × 11.29 100

«= 24.3269 =» 24.33

Award [2] for correct final answer.
Do not accept data booklet value (24.31).

b.

MgO(s) + H2O(l) → Mg(OH)2(s)

OR

MgO(s) + H2O(l) → Mg2+(aq) + 2OH(aq)

Accept  .

c.

from basic to acidic

through amphoteric

Accept “alkali/alkaline” for “basic”.
Accept “oxides of Na and Mg: basic AND oxide of Al: amphoteric” for M1.
Accept “oxides of non-metals/Si to Cl acidic” for M2.
Do not accept just “become more acidic”

d.

Mg3N2

Accept MgO2, Mg(OH)2, Mg(NOx)2, MgCO3.

e.

«3-D/giant» regularly repeating arrangement «of ions»
OR
lattice «of ions»
Accept “giant” for M1, unless “giant covalent” stated.

electrostatic attraction between oppositely charged ions
OR
electrostatic attraction between Mg2+ and O2– ions
Do not accept “ionic” without description.

f.

Anode (positive electrode):
2Cl → Cl2(g) + 2e

Cathode (negative electrode):
Mg2+ + 2e → Mg(l)

Penalize missing/incorrect state symbols at Cl2 and Mg once only.
Award [1 max] if equations are at wrong electrodes.
Accept Mg (g).

 

g.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.
[N/A]
d.
[N/A]
e.
[N/A]
f.
[N/A]
g.



Chlorine undergoes many reactions.

2.67g of manganese(IV) oxide was added to 200.0cm3 of 2.00moldm-3 HCl.

MnO2(s)+4HCl(aq)Cl2(g)+2H2O(l)+MnCl2(aq)

Chlorine gas reacts with water to produce hypochlorous acid and hydrochloric acid.

Cl2(g)+H2O(l)HClO(aq)+HCl(aq)

CCl2F2 is a common chlorofluorocarbon, CFC.

State the full electron configuration of the chlorine atom.

[1]
a(i).

State, giving a reason, whether the chlorine atom or the chloride ion has a larger radius.

[1]
a(ii).

Outline why the chlorine atom has a smaller atomic radius than the sulfur atom.

[2]
a(iii).

The mass spectrum of chlorine is shown.

NIST Mass Spectrometry Data Center Collection © 2014 copyright by the U.S. Secretary of Commerce on behalf of the United States of America. All rights reserved.

Outline the reason for the two peaks at m/z=35 and 37.

[1]
a(iv).

Explain the presence and relative abundance of the peak at m/z=74.

[2]
a(v).

Calculate the amount, in mol, of manganese(IV) oxide added.

[1]
b(i).

Determine the limiting reactant, showing your calculations.

[2]
b(ii).

Determine the excess amount, in mol, of the other reactant.

[1]
b(iii).

Calculate the volume of chlorine, in dm3, produced if the reaction is conducted at standard temperature and pressure (STP). Use section 2 of the data booklet.

[1]
b(iv).

State the oxidation state of manganese in MnO2 and MnCl2.

[2]
b(v).

Deduce, referring to oxidation states, whether MnO2 is an oxidizing or reducing agent.

[1]
b(vi).

Hypochlorous acid is considered a weak acid. Outline what is meant by the term weak acid.

 

[1]
c(i).

State the formula of the conjugate base of hypochlorous acid.

[1]
c(ii).

Calculate the concentration of H+(aq) in a HClOaq solution with a pH=3.61.

[1]
c(iii).

State the type of reaction occurring when ethane reacts with chlorine to produce chloroethane.

[1]
d(i).

Predict, giving a reason, whether ethane or chloroethane is more reactive.

[1]
d(ii).

Write the equation for the reaction of chloroethane with a dilute aqueous solution of sodium hydroxide.

[1]
d(iii).

Deduce the nucleophile for the reaction in d(iii).

[1]
d(iv).

Ethoxyethane (diethyl ether) can be used as a solvent for this conversion. Draw the structural formula of ethoxyethane

[1]
d(v).

Deduce the number of signals and their chemical shifts in the H1 NMR spectrum of ethoxyethane. Use section 27 of the data booklet.

[2]
d(vi).

Calculate the percentage by mass of chlorine in CCl2F2.

[2]
e(i).

Comment on how international cooperation has contributed to the lowering of CFC emissions responsible for ozone depletion.

[1]
e(ii).

Markscheme

1s22s22p63s23p5 ✔

Do not accept condensed electron configuration.

a(i).

Cl- AND more «electron–electron» repulsion ✔


Accept Cl- AND has an extra electron.

a(ii).

Cl has a greater nuclear charge/number of protons/Zeff «causing a stronger pull on the outer electrons» ✔

same number of shells
OR
same «outer» energy level
OR
similar shielding ✔

a(iii).

«two major» isotopes «of atomic mass 35 and 37» ✔

a(iv).

«diatomic» molecule composed of «two» chlorine-37 atoms ✔

chlorine-37 is the least abundant «isotope»
OR
low probability of two Cl37 «isotopes» occurring in a molecule ✔

a(v).

«2.67g86.94gmol-1=»0.0307«mol» ✔

b(i).

«nHCl=2.00moldm-3×0.2000dm3»=0.400mol 

«0.4004=»0.100mol AND MnO2 is the limiting reactant ✔

Accept other valid methods of determining the limiting reactant in M2.

b(ii).

«0.0307mol×4=0.123mol»

«0.400mol0.123mol=»0.277«mol» ✔

b(iii).

«0.0307mol×22.7dm3mol1=»0.697«dm3» ✔


Accept methods employing pV=nRT
.

b(iv).

MnO2: +4 ✔

MnCl2: +2 ✔

b(v).

oxidizing agent AND oxidation state of Mn changes from +4 to +2/decreases ✔

b(vi).

partially dissociates/ionizes «in water» ✔

c(i).

ClO- ✔

c(ii).

«[H+]=103.61=»2.5×104«moldm3» ✔

c(iii).

«free radical» substitution/SR


Do not accept electrophilic or nucleophilic substitution.

d(i).

chloroethane AND CCl bond is weaker/324kJmol1 than CH bond/414kJmol1
OR
chloroethane AND contains a polar bond ✔


Accept “chloroethane AND polar”.

d(ii).

CH3CH2Cl(l)+OH-(aq)CH3CH2OH(aq)+Cl-(aq)
OR
CH3CH2Cl(l)+NaOH(aq)CH3CH2OH(aq)+NaCl(aq) ✔

Accept use of C2H5Cl and C2H5OH/C2H6O in the equation.

d(iii).

hydroxide «ion»/OH-


Do not accept NaOH.

d(iv).

 / CH3CH2OCH2CH3

Accept (CH3CH2)2O.

d(v).

2 «signals» ✔

0.91.0«ppm» AND 3.33.7«ppm» 


Accept any values in the ranges.

Award [1 max] for two incorrect chemical shifts.

d(vi).

«M(CCl2F2) =»120.91«gmol1»  ✔

2×35.45gmol-1120.91gmol-1×100%=»58.64«%» ✔


Award [2] for correct final answer.

e(i).

Any of:

research «collaboration» for alternative technologies «to replace CFC
OR
technologies «developed»/data could be shared
OR
political pressure/Montreal Protocol/governments passing legislations ✔

 

Do not accept just “collaboration”.

Do not accept any reference to CFC as greenhouse gas or product of fossil fuel combustion.

Accept reference to specific measures, such as agreement on banning use/manufacture of CFCs.

e(ii).

Examiners report

Most candidates wrote the electron configuration of chlorine correctly.

a(i).

Only half of the candidates deduced that the chloride ion has a larger radius than the chlorine atom with a valid reason. Many candidates struggled with this question and decided that the extra electron in the chloride ion caused a greater attraction between the nucleus and the outer electrons.

a(ii).

Only about a third of the candidates identified the extra proton in the chlorine nucleus as the cause of the smaller atomic radius when compared to the sulfur atom, and only the stronger candidates also compared the shielding or the number of shells in the two atoms. Many candidates had a poor understanding of factors affecting atomic radius and could not explain the difference.

a(iii).

About 60% of the candidates recognized that the peaks at m/z 35 and 37 in the mass spectrum of chlorine are due to its isotopes. A few students wrote 'isomers' instead of 'isotopes'.

a(iv).

This was the lowest scoring question on the paper, that was also left blank by 10% of the candidates. About 20% of the candidates identified the peak at m/z = 74 to be due to a molecule made up of two 37Cl atoms. And only very few candidates commented that the low abundance of the peak was due to the low abundance of the 37Cl isotope. A common incorrect answer was that chlorine has an isotope of mass number 74.

a(v).

Most candidates were able to determine the number of moles of MnO2 using the mass.

b(i).

It was pleasing that the majority of the candidates were able to determine the limiting reactant by using the stoichiometric ratio.

b(ii).

Half of the candidates were able to determine the amount of excess reactant. Some candidates who determined the limiting reactant in the previous part correctly, forgot to use the stoichiometric ratio in this part, and ended up with incorrect answers.

b(iii).

60% of the candidates determined the volume of chlorine produced correctly. Some candidates made mistakes in the units when using PV = nRT and had a power of 10 error.

b(iv).

The majority of candidates were able to determine the oxidation states of Mn in the two compounds correctly.

b(v).

Less than half of the candidates were awarded the mark. Some did identify MnO2 as the oxidizing agent but did not give the explanation in terms of oxidation state as required in the question. Other candidates did not have an understanding of oxidizing and reducing agents. 

b(vi).

A very well answered question - 80% of candidates understood what is meant by the term weak acid. Incorrect answers included 'acids that have high pH'.

c(i).

Half of the candidates deduced the formula of the conjugate base of hypochlorous acid. Incorrect answers included H2O and HCl.

c(ii).

A well answered question. It was pleasing to see that 70% of the candidates were able to calculate [H+] from the given pH.

c(iii).

More than half of the candidates identified the type of reaction between ethane and chlorine as a substitution reaction. A few candidates lost the marks for writing 'electrophilic substitution' or 'nucleophilic substitutions'.

d(i).

This was a challenging question that was answered correctly by only 30% of the candidates. A variety of incorrect answers were seen such as 'chlorine is a halogen and hence it is reactive', and 'ethane is more reactive because it is an alkane'. For students who answered correctly, the polarity was the most frequently given reason.

d(ii).

Half of the candidates wrote the correct equation for the hydrolysis of chloroethane. Incorrect answers often included carbon dioxide and water as the products.

d(iii).

This was a highly discriminating question. Only 30% of the candidates were able to identify the hydroxide ion as the nucleophile in the hydrolysis of chloroethane. Incorrect answers included NaOH where the ion was not specified. 14% of the candidates left this question blank.

d(iv).

Half of the candidates were able to give the structural formula of ethoxyethane. Incorrect answers included methoxymethane, ketones and esters.

d(v).

Nearly half of the candidates were able to identify the number of signals obtained in the 1H NMR spectrum of ethoxyethane, obtaining the first mark of this question. Many candidates were awarded the mark as 'error carried forward' from an incorrect structure of ethoxyethane. The second mark for this question required candidates to look up values of chemical shift from the data booklet. Nearly a third of the candidates were able to match the chemical environments of the hydrogen atoms in ethoxyethane to those listed in the data booklet successfully. 

d(vi).

This was the highest scoring question in the paper. The majority of candidates were able to calculate the percentage by mass of chlorine in CCl2F2. Mistakes included incorrect rounding and arithmetic errors.

e(i).

This nature of science question was well answered by half of the candidates. Some teachers commented that the wording was rather vague. Incorrect answers were mainly assuming that CFCs were related to the combustion of fuels and greenhouse gas emissions.

e(ii).



Nickel catalyses the conversion of propanone to propan-2-ol.

Outline how a catalyst increases the rate of reaction.

[1]
a.

Explain why an increase in temperature increases the rate of reaction.

[2]
b.

Discuss, referring to intermolecular forces present, the relative volatility of propanone and propan-2-ol.

[3]
c.

The diagram shows an unlabelled voltaic cell for the reaction

Pb2+(aq)+Ni(s)Ni2+(aq)+Pb(s)

Label the diagram with the species in the equation.

 

[1]
d(i).

Suggest a metal that could replace nickel in a new half-cell and reverse the electron flow. Use section 25 of the data booklet.

[1]
d(ii).

Describe the bonding in metals.

[2]
d(iii).

Nickel alloys are used in aircraft gas turbines. Suggest a physical property altered by the addition of another metal to nickel.

[1]
d(iv).

Markscheme

provides an alternative pathway/mechanism AND lower Ea

Accept description of how catalyst lowers Ea (e.g. “reactants adsorb on surface «of catalyst»”, “reactant bonds weaken «when adsorbed»”).

a.

more/greater proportion of molecules with EEa

greater frequency/probability/chance of collisions «between the molecules»
OR
more collision per unit of time/second ✔

b.

hydrogen bonding/bonds «and dipole–dipole and London/dispersion forces are present in» propan-2-ol ✔

dipole–dipole «and London/dispersion are present in» propanone ✔

propan-2-ol less volatile AND hydrogen bonding/bonds stronger «than dipole–dipole »
OR
propan-2-ol less volatile AND «sum of all» intermolecular forces stronger ✔

c.

d(i).

Bi/Cu/Ag/Pd/Hg/Pt/Au  ✔

Accept Sb OR As.

d(ii).

electrostatic attraction ✔

between «a lattice of» metal/positive ions/cations AND «a sea of» delocalized electrons ✔


Accept “mobile/free electrons”.

d(iii).

Any of:

malleability/hardness
OR
«tensile» strength/ductility
OR
density
OR
thermal/electrical conductivity
OR
melting point
OR
thermal expansion ✔


Do not accept corrosion/reactivity or any chemical property.

Accept other specific physical properties.

d(iv).

Examiners report

A straight-forward question, however, half of the candidates only mentioned the lower activation energy and did not mention that this is through an alternative mechanism, so did not score the mark.

a.

Half of the candidates gained the mark about the increased frequency of collision. Fewer candidates also clarified that a larger proportion of molecules have the activation energy.

b.

Most candidates had the correct structure in their answers identifying the type of intermolecular forces in each compound and then comparing the strength of the two and reaching a conclusion. Some candidates did not know what was meant by volatile. Some candidates stated London dispersion forces in propanone instead of dipole-dipole.

c.

60% of the candidates obtained the mark. Some candidates labelled the electrodes as ions indicating they do not understand the structure of a voltaic cell.

d(i).

70% of the candidates answered correctly. The common mistake was to select a more reactive metal instead.

d(ii).

The mean mark on the question was 1.0 out of 2 marks. Mistakes included not mentioning the 'electrostatic attraction' and talking about 'nuclei attracting the delocalised electrons'. The weakest candidates discussed aspects of ionic and/or covalent bonding.

d(iii).

80% obtained the mark. Many candidates wrote more than one property, which should be discouraged. Incorrect answers included chemical properties such as reactivity.

d(iv).



Ethane-1,2-diol, HOCH2CH2OH, has a wide variety of uses including the removal of ice from aircraft and heat transfer in a solar cell.

Ethane-1,2-diol can be formed according to the following reaction.

2CO (g) + 3H(g)   HOCH2CH2OH (g)

(i) Deduce the equilibrium constant expression, Kc, for this reaction.

 

(ii) State how increasing the pressure of the reaction mixture at constant temperature will affect the position of equilibrium and the value of Kc.

Position of equilibrium:

Kc:

 

(iii) Calculate the enthalpy change, ΔHθ, in kJ, for this reaction using section 11 of the data booklet. The bond enthalpy of the carbon–oxygen bond in CO (g) is 1077kJmol-1.

 

(iv) The enthalpy change, ΔHθ, for the following similar reaction is –233.8 kJ.

2CO(g) + 3H2(g)   HOCH2CH2OH (l)

Deduce why this value differs from your answer to (a)(iii).

[7]
a.

Determine the average oxidation state of carbon in ethene and in ethane-1,2-diol.

Ethene:

Ethane-1,2-diol:

[2]
b.

Explain why the boiling point of ethane-1,2-diol is significantly greater than that of ethene.

[2]
c.

Ethane-1,2-diol can be oxidized first to ethanedioic acid, (COOH)2, and then to carbon dioxide and water. Suggest the reagents to oxidize ethane-1,2-diol.

[1]
d.

Markscheme

(i)
K C =≫ [ HOC H 2 C H 2 OH ] [ CO ] 2 × [ H 2 ] 3  

 

(ii)
Position of equilibrium: moves to right OR favours product
Kc: no change OR is a constant at constant temperature

 

(iii)
Bonds broken: 2C≡O + 3(H-H) / 2(1077kJmol-1) + 3(436kJmol-1) / 3462 «kJ»

Bonds formed: 2(C-O) + 2(O-H) + 4(C-H) + (C-C) / 2(358kJmol-1) + 2(463kJmol-1) + 4(414kJmol-1) + 346kJmol-1 / 3644 «kJ»

«Enthalpy change = bonds broken - bonds formed = 3462 kJ - 3644 kJ =» -182 «kJ»

Award [3] for correct final answer.
Award [2 max] for «+»182 «kJ».


(iv)
in (a)(iii) gas is formed and in (a)(iv) liquid is formed
OR
products are in different states
OR
conversion of gas to liquid is exothermic
OR
conversion of liquid to gas is endothermic
OR
enthalpy of vapourisation needs to be taken into account

Accept product is «now» a liquid.
Accept answers referring to bond enthalpies being means/averages.

a.

Ethene: –2

Ethane-1,2-diol: –1

Do not accept 2–, 1– respectively.

 

b.

ethane-1,2-diol can hydrogen bond to other molecules «and ethene cannot»

OR

ethane-1,2-diol has «significantly» greater van der Waals forces

Accept converse arguments.
Award [0] if answer implies covalent bonds are broken

hydrogen bonding is «significantly» stronger than other intermolecular forces

c.

acidified «potassium» dichromate«(VI)»/H+ AND K2Cr2O7/H+ AND Cr2O72-

OR

«acidified potassium» manganate(VII)/ «H+» KMnO4 /«H+» MnO4-

Accept Accept H2SO4 or H3PO4 for H+.
Accept “permanganate” for “manganate(VII)”.

d.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.
[N/A]
d.